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Find the length of a simple pendulum whose period is 1.00 s at a location where g = 9.82 m/s2.
To obtain the length (L) of a simple pendulum, substitute 1.00 s for time period T and 9.82 m/s2 for acceleration due to gravity g in the equation L = (T/2π)2 g,L = (T/2π)2 g = (1.00 s/2(3.14))2 (9.82 m/s2) = 0.249 mFrom the above observation we conclude that, the length of the simple pendulum would be, 0.249 m.
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