Find the length of a simple pendulum whose period is 1.00 s at a location where g = 9.82 m/s 2 .

Question

Jitender Pal · Answer

To obtain the length (L) of a simple pendulum, substitute 1.00 s for time period T and 9.82 m/s2 for acceleration due to gravity g in the equation L = (T/2π)² g,
L = (T/2π)² g
= (1.00 s/2(3.14))² (9.82 m/s²)
= 0.249 m
From the above observation we conclude that, the length of the simple pendulum would be, 0.249 m.

Tahir ayub · Answer

For a mass spring system placed on a smooth horizontal surface oscillating with amplitude . At what displacement from the mean position its kinetic energy is equal to its elastic poltential energy

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Find the length of a simple pendulum whose period is 1.00 s at a location where g = 9.82 m/s 2 .

Find the length of a simple pendulum whose period is 1.00 s at a location where g = 9.82 m/s².

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Find the length of a simple pendulum whose period is 1.00 s at a location where g = 9.82 m/s 2 .

Find the length of a simple pendulum whose period is 1.00 s at a location where g = 9.82 m/s2.

2 Answers

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Find the length of a simple pendulum whose period is 1.00 s at a location where g = 9.82 m/s².