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Find the length of a simple pendulum whose period is 1.00 s at a location where g = 9.82 m/s 2 .

Find the length of a simple pendulum whose period is 1.00 s at a location where g = 9.82 m/s2.

Grade:11

2 Answers

Jitender Pal
askIITians Faculty 365 Points
8 years ago
To obtain the length (L) of a simple pendulum, substitute 1.00 s for time period T and 9.82 m/s2 for acceleration due to gravity g in the equation L = (T/2π)2 g,
L = (T/2π)2 g
= (1.00 s/2(3.14))2 (9.82 m/s2)
= 0.249 m
From the above observation we conclude that, the length of the simple pendulum would be, 0.249 m.
Tahir ayub
13 Points
2 years ago
For a mass spring system placed on a smooth horizontal surface oscillating with amplitude . At what displacement from the mean position its kinetic energy is equal to its elastic poltential energy

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