Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Find the length of a simple pendulum whose period is 1.00 s at a location where g = 9.82 m/s 2 .

Find the length of a simple pendulum whose period is 1.00 s at a location where g = 9.82 m/s2.

Grade:11

2 Answers

Jitender Pal
askIITians Faculty 365 Points
6 years ago
To obtain the length (L) of a simple pendulum, substitute 1.00 s for time period T and 9.82 m/s2 for acceleration due to gravity g in the equation L = (T/2π)2 g,
L = (T/2π)2 g
= (1.00 s/2(3.14))2 (9.82 m/s2)
= 0.249 m
From the above observation we conclude that, the length of the simple pendulum would be, 0.249 m.
Tahir ayub
13 Points
3 months ago
For a mass spring system placed on a smooth horizontal surface oscillating with amplitude . At what displacement from the mean position its kinetic energy is equal to its elastic poltential energy

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free