Jitender Pal
Last Activity: 10 Years ago
The resonance column apparatus is equivalent to a closed organ pipe.
Here l = 80 cm = 10 × 10^–2 m ; v = 320 m/s
⇒n base 0 = V/4l = 320/4 * 50 * 10^-2 = 100 Hz
So the frequency of the other harmonics are odd multiple of n base 0 = (2n + 1) 100 Hz
According to the question, the harmonic should be between 20 Hz and 2 KHz.