Equations of SHM A particle is subjected to two SHMs x 1 = A 1 sin wt and x 2 = A 2 sin (wt + 180/4). The resultant SHM will have an amplitude of treat w as omega Answer is( A 1 2 +A2 2 + (2) 1/2 A 1 A 2 ) 1/2 how A particle moves according to the law x=a cos pi.t/2. The distance covered by it in the time interval between t =0 to t=3 sec is 1)2a 2)3a 3)4a 4)a which is correct answers please.

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Saurabh Koranglekar · Answer

Arun · Answer

x = A sin ω t (i) y = A sin ( 2 ω t + π / 2 ) = A cos 2 ω t = A ( 1 − 2 sin 2 ω t ) From Eq. (i) sin ω t = A x ​ ∴ y = A ( 1 − A 2 2 x 2 ​ ) Thanks and regards

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