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Equations of SHM A particle is subjected to two SHMs x 1 = A 1 sin wt and x 2 = A 2 sin (wt + 180/4). The resultant SHM will have an amplitude of treat w as omega Answer is( A 1 2 +A2 2 + (2) 1/2 A 1 A 2 ) 1/2 how A particle moves according to the law x=a cos pi.t/2. The distance covered by it in the time interval between t =0 to t=3 sec is 1)2a 2)3a 3)4a 4)a which is correct answers please.

Equations of SHM
  1. A particle is subjected to two SHMs x1 = A1sin wt and x2 = A2 sin (wt + 180/4). The resultant SHM will have an amplitude of treat w as omega Answer is( A12 +A22+ (2)1/2A1 A2) 1/2 how
  2. A particle moves according to the law x=a cos pi.t/2. The distance covered by it in the time interval between t =0 to t=3 sec is 1)2a  2)3a 3)4a  4)a which is correct answers please. 

Grade:11

2 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
2 years ago
576-1443_1.PNG
Arun
25758 Points
2 years ago
x=Asinωt          (i)
y=Asin(2ωt+π/2)
   =Acos2ωt
   =A(1−2sin2ωt)
From Eq. (i)
sinωt=Ax​
∴   y=A(1−A22x2​)
 
Thanks and regards

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