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Grade: 11
        
Equations of SHM
  1. A particle is subjected to two SHMs x1 = A1sin wt and x2 = A2 sin (wt + 180/4). The resultant SHM will have an amplitude of treat w as omega Answer is( A1+A22+ (2)1/2AA2) 1/2 how
  2. A particle moves according to the law x=a cos pi.t/2. The distance covered by it in the time interval between t =0 to t=3 sec is 1)2a  2)3a 3)4a  4)a which is correct answers please. 
one year ago

Answers : (2)

Saurabh Koranglekar
askIITians Faculty
8369 Points
							576-1443_1.PNG
						
2 months ago
Arun
24716 Points
							
x=Asinωt          (i)
y=Asin(2ωt+π/2)
   =Acos2ωt
   =A(12sin2ωt)
From Eq. (i)
sinωt=Ax
   y=A(1A22x2)
 
Thanks and regards
2 months ago
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