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Grade 11Wave Motion

Consider the situation of the previous problem. If the mirror reflects only 64% of the light energy falling on it, what will be the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen?

Profile image of Radhika Batra
12 Years agoGrade 11
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1 Answer

Profile image of Kevin Nash
12 Years ago
Sol. Given that, the mirror reflects 64% of energy (intensity) of the light. So, l base 1/l base 2 = 0.64 = 16/25 ⇒ r base 1/r base 2 = 4/5 So, l base max/l base min = (r base 1 + r base 2)^2/( r base 1 - r base 2)^2 = 81: 1.

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