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Consider the situation of the previous problem. If the mirror reflects only 64% of the light energy falling on it, what will be the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen?

Consider the situation of the previous problem. If the mirror reflects only 64% of the light energy falling on it, what will be the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen?

Grade:11

1 Answers

Kevin Nash
askIITians Faculty 332 Points
7 years ago
Sol. Given that, the mirror reflects 64% of energy (intensity) of the light. So, l base 1/l base 2 = 0.64 = 16/25 ⇒ r base 1/r base 2 = 4/5 So, l base max/l base min = (r base 1 + r base 2)^2/( r base 1 - r base 2)^2 = 81: 1.

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