Consider the situation of the previous problem. If the mirror reflects only 64% of the light energy falling on it, what will be the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen?

Question

Kevin Nash · Answer

Sol. Given that, the mirror reflects 64% of energy (intensity) of the light. So, l base 1/l base 2 = 0.64 = 16/25 ⇒ r base 1/r base 2 = 4/5 So, l base max/l base min = (r base 1 + r base 2)^2/( r base 1 - r base 2)^2 = 81: 1.

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Consider the situation of the previous problem. If the mirror reflects only 64% of the light energy falling on it, what will be the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen?

Consider the situation of the previous problem. If the mirror reflects only 64% of the light energy falling on it, what will be the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen?

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