0

Guest

Courses New

Consider the situation of the previous problem. If the mirror reflects only 64% of the light energy falling on it, what will be the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen?

Consider the situation of the previous problem. If the mirror reflects only 64% of the light energy falling on it, what will be the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen?

Grade:11

1 Answers

Kevin Nash
askIITians Faculty 332 Points
8 years ago
Sol. Given that, the mirror reflects 64% of energy (intensity) of the light. So, l base 1/l base 2 = 0.64 = 16/25 ⇒ r base 1/r base 2 = 4/5 So, l base max/l base min = (r base 1 + r base 2)^2/( r base 1 - r base 2)^2 = 81: 1.

Think You Can Provide A Better Answer ?

Other Related Questions on Wave Motion

View all Questions »

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More