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calculate the critical angle and an angle of entry for an optical fibre having core of refractive index 1.50 and cladding of refractive index 1.48a. 30 degree b. 14.2 degreec. 5 deg d. 45 degree

calculate the critical angle and an angle of entry for an optical fibre having core of refractive index 1.50 and cladding of refractive index 1.48a. 30 degree b. 14.2 degreec. 5 deg d. 45 degree

Grade:12th pass

1 Answers

Khimraj
3007 Points
3 years ago
Let n1 = refractive index of core = 1.50
n2 = refractive index of cladding = 1.48
critical angle is given by
sin\Theta _{c} = n2/n1
So \Theta _{c} = sin-1(1.48/1.50) = 80.63o
and angle of entry is given by
sin\alpha = \sqrt{n_{1}^{2} - n_{2}^{2}}
\alpha = 14.2o

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