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At a certain harbor, the tides cause the ocean surface to rise and fall in simple harmonic motion, with a period of 12.5 h. How long does it take for the water to fall from its maximum height to one-half its maximum height above its average (equilibrium) level?

```
5 years ago

```							To obtain t in terms of w, substitute w = 2π/T in the equation t = π/3w,t = π/3w= π/3(2π/T)= T/6To find out t (time), substitute 12.5 h for period T in the equation t = T/6,t = T/6=12.5 h/6=2.08 hFrom the above observation we conclude that, it will take 2.08 h for the water to fall from its maximum height to one-half its maximum height above its average (equilibrium) level.
```
5 years ago
```							To obtain t in terms of w, substitute w = 2π/T in the equation t = π/3w,t = π/3w= π/3(2π/T)= T/6To find out t (time), substitute 12.5 h for period T in the equation t = T/6,t = T/6=12.5 h/6=2.08 hFrom the above observation we conclude that, it will take 2.08 h for the water to fall from its maximum height to one-half its maximum height above its average (equilibrium) level.
```
5 years ago
```													 						To obtain t in terms of w, substitute w = 2π/T in the equation t = π/3w, t = π/3w = π/3(2π/T) = T/6 To find out t (time), substitute 12.5 h for period T in the equation t =...
```
5 years ago
```							To obtain t in terms of w, substitute w = 2π/T in the equation t = π/3w, t = π/3w = π/3(2π/T) = T/6 To find out t (time), substitute 12.5 h for period T in the equation t =...
```
5 years ago
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