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Acceleration of point x = 2m of a transverse wave is 5 j ^ m/s^2 and the slope of the waveform is given by dy/dx = 5sin (pi*x)/12 . Then the speed of the point at that instant is given in m/s as

Acceleration of point x = 2m of a transverse wave is 5 j^ m/s^2 and the slope of the waveform is given by dy/dx = 5sin (pi*x)/12 . Then the speed of the point at that instant is given in m/s as
 
 

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1 Answers

Abhishek Kumar
askIITians Faculty 255 Points
7 years ago
Vp = -Vy dy/dx
Vp = Velocity of the particle
Vy = Velocity of the wave
Solve.

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