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`        A trolley of mass m= 5kg is connected to a block of 2kg with the help of massless inextensible spring over a light frictionless pulley. Calculate the tension of the string. Assume no friction `
one year ago

```							Acceleration of the system= (supporting force-opposing force)/total mass.So,accleration=(5g-2g)/(5+2)                           =30/7So tension in the string is T=5 (g-a)                                                 =5 (10-30/7)                                                  =(5×40)/7                                                  =200/7                                                     =5×40
```
one year ago
```							Acceleration of the system = (total force /total mass)So acceleration =2gsin \$/7                             =(2×10×4/5)/7                             =16/7          For the 5kg block T=5a                                           T=5×16/7                                           T=80/7
```
one year ago
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