Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A trolley of mass m= 5kg is connected to a block of 2kg with the help of massless inextensible spring over a light frictionless pulley. Calculate the tension of the string. Assume no friction

A trolley of mass m= 5kg is connected to a block of 2kg with the help of massless inextensible spring over a light frictionless pulley. Calculate the tension of the string. Assume no friction
 

Question Image
Grade:12

2 Answers

Akash Nayak
16 Points
one year ago
Acceleration of the system= (supporting force-opposing force)/total mass.
So,accleration=(5g-2g)/(5+2)
                           =30/7
So tension in the string is T=5 (g-a)
                                                 =5 (10-30/7)
                                                  =(5×40)/7
                                                  =200/7
 
 
 
 
                                                 =5×40
Akash Nayak
16 Points
one year ago
Acceleration of the system = (total force /total mass)
So acceleration =2gsin $/7
                             =(2×10×4/5)/7
                             =16/7
          For the 5kg block T=5a
                                           T=5×16/7
                                           T=80/7

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free