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Grade: 12
        
A trolley of mass m= 5kg is connected to a block of 2kg with the help of massless inextensible spring over a light frictionless pulley. Calculate the tension of the string. Assume no friction
 
6 months ago

Answers : (2)

Akash Nayak
16 Points
							
Acceleration of the system= (supporting force-opposing force)/total mass.
So,accleration=(5g-2g)/(5+2)
                           =30/7
So tension in the string is T=5 (g-a)
                                                 =5 (10-30/7)
                                                  =(5×40)/7
                                                  =200/7
 
 
 
 
                                                 =5×40
6 months ago
Akash Nayak
16 Points
							
Acceleration of the system = (total force /total mass)
So acceleration =2gsin $/7
                             =(2×10×4/5)/7
                             =16/7
          For the 5kg block T=5a
                                           T=5×16/7
                                           T=80/7
6 months ago
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