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A transverse wave is described by equation y=asin2π[vt-{x÷lambda}]....The maximum velocity of particlewill be 4times of velocity of wave provided...If lamda equals to

Anushka , 8 Years ago
Grade 12
anser 1 Answers
Sahithi Venkatesan
velocity of particle =( -slope )(velocity of wave).  dy/dx= – a/lambda.  v of particle max=4v.   4=a/lambda.    lambda =a/4
Last Activity: 8 Years ago
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