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A transverse wave is described by equation y=asin2π[vt-{x÷lambda}]....The maximum velocity of particlewill be 4times of velocity of wave provided...If lamda equals to

A transverse wave is described by equation y=asin2π[vt-{x÷lambda}]....The maximum velocity of particlewill be 4times of velocity of wave provided...If lamda equals to

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Grade:12

1 Answers

Sahithi Venkatesan
34 Points
4 years ago
velocity of particle =( -slope )(velocity of wave).  dy/dx= – a/lambda.  v of particle max=4v.   4=a/lambda.    lambda =a/4

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