Navjyot Kalra
Last Activity: 10 Years ago
Sol. . l = 40 cm, mass = 10 g
∴ mass per unit length, m = 10 / 40 = 1/4 (g/cm)
spring constant K = 160 N/m
deflection = x = 1 cm = 0.01 m
⇒ T = kx = 160 * 0.01 = 1.6 N = 16 * 104 dyne
Again v = √(T /m) = √(16 *104 /(1/ 4) = 8 * 102 cm/s = 800 cm/s
∴ Time taken by the pulse to reach the spring
t = 40/800 = 1/20 = 0/05 sec.