Navjyot Kalra
Last Activity: 11 Years ago
Sol. a) Here given n = 100, v = 350 m/s
⇒ λ = v/m = 350/100 = 3.5
In 2.5 ms, the distance travelled by the particle is given by
∆* = 350 * 2.5 * 10^-3
So, phase difference ∅ = 2π/λ * ∆* ⇒ 2π/(350/100) * 350 * 2.5 * 10^-3 = (π/2).
b) In the second case, Given ∆η = 10 cm = 10^-1 m.
So, ϕ = 2π/*∆* = 2π * 10^-1/(350/100) = 2π/35.