A sorce,S of sound,having a natural frequency n,first approches ,and then moves fast,a stationary observer O.The source moves with a constant velocity Vs of sound,in air, is V. Find the magnitude of change delta n in the apparent frequency of the source,at the instant it goes past O.

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Shivansh · Answer

The frequency of approach will be f1= nV/(V-Vs) f2= nV/(V+Vs) Difference will be- f1-f2 = 2nV*Vs/(V 2 -Vs 2 )

Shivansh · Answer

f2 as written above is the frequency heard after the source moves past

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A sorce,S of sound,having a natural frequency n,first approches ,and then moves fast,a stationary observer O.The source moves with a constant velocity Vs of sound,in air, is V. Find the magnitude of change delta n in the apparent frequency of the source,at the instant it goes past O.

A sorce,S of sound,having a natural frequency n,first approches ,and then moves fast,a stationary observer O.The source moves with a constant velocity Vs of sound,in air, is V.
Find the magnitude of change delta n in the apparent frequency of the source,at the instant it goes past O.

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A sorce,S of sound,having a natural frequency n,first approches ,and then moves fast,a stationary observer O.The source moves with a constant velocity Vs of sound,in air, is V. Find the magnitude of change delta n in the apparent frequency of the source,at the instant it goes past O.

A sorce,S of sound,having a natural frequency n,first approches ,and then moves fast,a stationary observer O.The source moves with a constant velocity Vs of sound,in air, is V.Find the magnitude of change delta n in the apparent frequency of the source,at the instant it goes past O.

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A sorce,S of sound,having a natural frequency n,first approches ,and then moves fast,a stationary observer O.The source moves with a constant velocity Vs of sound,in air, is V.
Find the magnitude of change delta n in the apparent frequency of the source,at the instant it goes past O.