Flag Wave Motion> A simple pendulum of length L and mass m ...
question mark

A simple pendulum of length L and mass m is suspended in a car that is traveling with a constant speed v around a circle of radius R. If the pendulum endergoes small oscillations in a radial direction about its equilibrium position, what will its frequency of oscillation be?

Hrishant Goswami , 10 Years ago
Grade 10
anser 1 Answers
Navjyot Kalra

Last Activity: 10 Years ago

(a)
The period T of a simple pendulum is defined as,
T = 2π√L/g
Here L is the length of the pendulum and g is the free fall acceleration.
So, the period of the simple pendulum is independent of the mass m of the suspended particle.
Thus the mass, m, of the cord attached to the bob, of mass M, of a pendulum will not affect the period over that for a simple pendulum in which m=0.
(b)
In a simple pendulum, the period T will be,
T = 2π√L/g
Here L is the length of the pendulum and g is the free fall acceleration.
The period of the simple pendulum is independent of the mass m of the suspended particle.
A simple pendulum is an idealized body consisting of a particle having mass M, suspended by a light inextensible cord. When pulled to one side of its equilibrium position and released, the pendulum swings in a vertical plane under the influence of gravity. The motion is periodic and oscillatory. As here, a cord of length L swinging without anything on the end (M=0), therefore, it will not an ideal simple pendulum anymore. Because, an ideal pendulum always contain a particle having mass M suspended by a light inextensible cord.




star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments