A SIMPLE PENDULUM HAS TIME PERIOD OF T1.THE POINT OF SUSPENSION IS NOW MOVED UPWARDS ACCORDING TO EQUATION Y=KT^2 WHERE K=1M/S.IF NEW TIME PEROD IS T2 THEN RATION OF T1/T2 IS

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Arun · Answer

Dear Aniket y = kt² , d²y/dt² = 2k . As k = 1m/s², a y = 2 m/s² . T1 = 2π √ l/g and T2 = 2π √ L/g +a y , therefore , T1²/ T2² = 10 + 2/10 = 6/5 . Regards Arun (askIITians forum expert)

Yash Chourasiya · Answer

Dear Student Please see the solution in the attachment. I hope this answer will help you. Thanks & Regards Yash Chourasiya

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A SIMPLE PENDULUM HAS TIME PERIOD OF T1.THE POINT OF SUSPENSION IS NOW MOVED UPWARDS ACCORDING TO EQUATION Y=KT^2 WHERE K=1M/S.IF NEW TIME PEROD IS T2 THEN RATION OF T1/T2 IS

A SIMPLE PENDULUM HAS TIME PERIOD OF T1.THE POINT OF SUSPENSION IS NOW MOVED UPWARDS ACCORDING TO EQUATION Y=KT^2 WHERE K=1M/S.IF NEW TIME PEROD IS T2 THEN RATION OF T1/T2 IS

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