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A SIMPLE PENDULUM HAS TIME PERIOD OF T1.THE POINT OF SUSPENSION IS NOW MOVED UPWARDS ACCORDING TO EQUATION Y=KT^2 WHERE K=1M/S.IF NEW TIME PEROD IS T2 THEN RATION OF T1/T2 IS

 A SIMPLE PENDULUM HAS TIME PERIOD OF T1.THE POINT OF SUSPENSION IS NOW MOVED UPWARDS ACCORDING TO EQUATION Y=KT^2 WHERE K=1M/S.IF NEW TIME PEROD IS T2 THEN RATION OF T1/T2 IS

Grade:12

2 Answers

Arun
25757 Points
5 years ago
Dear Aniket
 
y = kt² , d²y/dt² = 2k . As k = 1m/s²,  ay = 2 m/s² .
T1 = 2π √ l/g  and   T2  =  2π √ L/g +ay , therefore ,  T1²/ T2² = 10 + 2/10  = 6/5 . 
 
 
Regards
Arun (askIITians forum expert)
Yash Chourasiya
askIITians Faculty 256 Points
2 years ago
Dear Student

Please see the solution in the attachment.
643-2204_Untitled.png

I hope this answer will help you.
Thanks & Regards
Yash Chourasiya

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