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A SIMPLE PENDULUM HAS TIME PERIOD OF T1.THE POINT OF SUSPENSION IS NOW MOVED UPWARDS ACCORDING TO EQUATION Y=KT^2 WHERE K=1M/S.IF NEW TIME PEROD IS T2 THEN RATION OF T1/T2 IS
Dear Aniket y = kt² , d²y/dt² = 2k . As k = 1m/s², ay = 2 m/s² .T1 = 2π √ l/g and T2 = 2π √ L/g +ay , therefore , T1²/ T2² = 10 + 2/10 = 6/5 . RegardsArun (askIITians forum expert)
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