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A simple pendulum 50 cm long is suspended from the roof of a cart accelerating in the horizontal direction with constant acceleration root(3) g m/s2 . The period of small oscillations of the pendulum about its equilibrium position is (g = pi^2 m/s2) : ans: 1 sec. How??

A simple pendulum 50 cm long is suspended from the roof of a cart accelerating in the horizontal direction with constant acceleration root(3) g m/s2 . The period of small oscillations of the pendulum about its equilibrium position is (g = pi^2 m/s2) :
 
ans: 1 sec.
 
How??

Question Image
Grade:11

1 Answers

Sarthak Gupta
11 Points
3 years ago
Take vector summation of root3 g and g with angle 90° . g eff will be 2g. Then apply T= 2pi root(l/g eff)

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