A resonance tube is resonated with tuning fork of frequency 256Hz, If the lengths of the resonating air columns are 32cm and 100cm,then end correction wil be.

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Arun · Answer

Dear student 32 + e = lambda /4 also 100 + e = 3 * lambda/4 now you can solve this, in case of any difficulty please feel free to ask

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A resonance tube is resonated with tuning fork of frequency 256Hz, If the lengths of the resonating air columns are 32cm and 100cm,then end correction wil be.

A resonance tube is resonated with tuning fork of frequency 256Hz, If the lengths of the resonating air columns are 32cm and 100cm,then end correction wil be.

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A resonance tube is resonated with tuning fork of frequency 256Hz, If the lengths of the resonating air columns are 32cm and 100cm,then end correction wil be.

A resonance tube is resonated with tuning fork of frequency 256Hz, If the lengths of the resonating air columns are 32cm and 100cm,then end correction wil be.

1 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Wave Motion

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

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