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A projectile projected at some angle with vel. 50m/s crosses a 20m wall after 4s from the time of projection. The angle of projection of particle will be

Arushi Singh , 10 Years ago
Grade 12
anser 1 Answers
Arun Kumar

Last Activity: 10 Years ago

Hello Student,
\\ \\$we will answer first question only for the second $ \\$make another post$ \\20=v_y4-5*4^2 \\5=v_y-20 \\=>v_y=25m/s \\=>50sin\theta=25 \\=>sin\theta=1/2 \\
Thanks & Regards
Arun Kumar
Btech, IIT Delhi
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