Click to Chat
1800-2000-838
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A particle of mass 10g is placed in potential field given by V= (50x^2+100)erg/g. what will be the frequency of oscillation?
Considering the particle mass of 10g, the actual V = (50x^2 +100 erg)*10 = 500x^2 +1000 erg.Now the frequency is given by E = h* (freequency)Freequency = (500*x^2 + 1000)/6.626 * 10^-27 erg-secondsHence Freequency = (75.46*x^2+150.9) * 10^27/sec
P.E=mV=10(50x^2+100)=500x^2+1000F=-dU/dxF=-1000xF=mama=-1000xa=-1000x/10=-100xa=-w(omega)^2xw=√100=10f=w/2π=10/2π=3.2sec^(-1)
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -