A particle of mass 10 gram is placed in a field where potential energy is given by U= (50x 2 + 20x + 3) j what will be time period for the oscillation of particle

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Chaman patel · Answer

Differentiating the equation of U we get dU/dX =100X.Therefore F=100x. w2a=100xTherefore w= √100T=2π/√100

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A particle of mass 10 gram is placed in a field where potential energy is given by U= (50x 2 + 20x + 3) j what will be time period for the oscillation of particle

A particle of mass 10 gram is placed in a field where potential energy is given by U= (50x²+ 20x + 3) j what will be time period for the oscillation of particle

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A particle of mass 10 gram is placed in a field where potential energy is given by U= (50x 2 + 20x + 3) j what will be time period for the oscillation of particle

A particle of mass 10 gram is placed in a field where potential energy is given by U= (50x2 + 20x + 3) j what will be time period for the oscillation of particle

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A particle of mass 10 gram is placed in a field where potential energy is given by U= (50x²+ 20x + 3) j what will be time period for the oscillation of particle