a particle of mass 0.5 gm is located at x1=15 at T1=5 sec and at X2=33m at T2=13 sec its average velocity is a. 2.45 m/s b. 2.25m/s c. 4.45 m/s ans is optn a..... i have formulas Vav=V1+V2/2 and s=v*t

Question

Eshan · Answer

Average velocity is that constant velocity with which the particle must have travelled to cause the same displacement in the same amount of time.

Average velocity=Total displacement/Total time
= $\dfrac{33-15}{13-5}m/s$ =2.25m/s

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a particle of mass 0.5 gm is located at x1=15 at T1=5 sec and at X2=33m at T2=13 sec its average velocity is a. 2.45 m/s b. 2.25m/s c. 4.45 m/s ans is optn a..... i have formulas Vav=V1+V2/2 and s=v*t

a particle of mass 0.5 gm is located at x1=15 at T1=5 sec and at X2=33m at T2=13 sec its average velocity is a. 2.45 m/s b. 2.25m/s c. 4.45 m/s ans is optn a..... i have formulas Vav=V1+V2/2 and s=v*t

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a particle of mass 0.5 gm is located at x1=15 at T1=5 sec and at X2=33m at T2=13 sec its average velocity is a. 2.45 m/s b. 2.25m/s c. 4.45 m/s ans is optn a..... i have formulas Vav=V1+V2/2 and s=v*t

a particle of mass 0.5 gm is located at x1=15 at T1=5 sec and at X2=33m at T2=13 sec its average velocity is a. 2.45 m/s b. 2.25m/s c. 4.45 m/s ans is optn a..... i have formulas Vav=V1+V2/2 and s=v*t

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