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Grade: 12th pass
        A particle of mass 0.1kg is executing SHM of amplitude 1m and period 0.2 sec what max. Value of force acting on it? If oscillation is produced by spring what is the force constant of spring
3 months ago

Answers : (1)

Arun
9288 Points
							
Dear student
 
Maximum acceleration
a(max) = w² *a = 4\pi² A/ T² = 4 *(3.14)² * 1/(0.2)²
 
F(max) = m * a(max) = 0.1 * 4 * (3.14)²*1/(0.2)²
 = 98.6 N
 
Force constant k = Fmax/A = 98.6/1
 = 98.6 N/m
 
 
Regards
Arun (askIITians forum expert)
 
3 months ago
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