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A particle moves on the x axis according to the equation x=x0sin2(wt). The motion is simple harmonic(1) with amplitude x0(2) with amplitude 2x0(3) with time period 2pi/w(4) with time period pi/w Please help

MANAV S , 6 Years ago
Grade 12
anser 2 Answers
Khimraj

Last Activity: 6 Years ago

x = xosin2(wt)
x = xo(1 – cos2wt)/2
So x = xo/2 – (½)xocos(2wt)
SO its amplityde is xo/2
and 2w = 2pi/T
So T = pi/w.
So correct option is (4).
Hopeit clears. If you like anser then please approve it.

Kushagra Madhukar

Last Activity: 4 Years ago

Dear student,
Please find the answer to your question.
 
x = xosin2(wt)
x = xo(1 – cos2wt)/2
So x = xo/2 – (½)xocos(2wt)
Hence its amplitude is xo/2
and 2w = 2pi/T
=> T = pi/w.
Hence, correct option is (4).
 
Thanks and regards,
Kushagra

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