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A particle is projected in the xy plane with the x axis along vertical, the point of projection in orign . The equation of the path is y = root3 – g x ^2 divided by two where y and x are in meters . Then the speed of projection in ms^-1 is a)2 B) root 3 c)4 d) root3 by 2


one year ago

							A particle is projected in xy plane with x axis along vertical the point of projection is origin.the equation of the path is  this is parabolic equation. hence question is based on projectile motion  if a particle is projected with speed u at an angle  to the vertical  equation of the path of the particle is given byon camparing the both equation we get  and so,   and now Hence, speed of projection is 2m/s

one year ago
							Trajectory of projectile motion when u is intial speed inclined Ф angle with horizontalthe equation of projectile is : y = xTanФ - gx²/ 2u²Cos²Фand the given equation is : y = √3x - gx²/2on comparing both the equations ,we getTanФ = √3so, Ф = 60°HENCE, the angle of projectile is 60°and 2u²Cos²Ф = 2so u²Cos²Ф = 1u²cos²60° = 1u²*(1/2)² = 1u² = 2²so, u = 2

one year ago
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