MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        
A particle is projected in the xy plane with the x axis along vertical, the point of projection in orign . The equation of  the path is y =root3 – g x ^2 divided by two where y and x are in meters . Then the speed of projection in ms^-1 is
 
a)2                                          B)root 3                                    
 
c)4                                           d)root3 by 2
one month ago

Answers : (2)

Md Mushahid
16 Points
							
A particle is projected in xy plane with x axis along vertical the point of projection is origin.
the equation of the path is y = \sqrt{3} x-\frac{g}{2} x ^{2} this is parabolic equation. hence question is based on projectile motion  
if a particle is projected with speed u at an angle \alpha to the vertical  equation of the path of the particle is given byy =x\tan \alpha - \frac{g}{2u^{2}\times \cos ^{\alpha }}x^{2}
on camparing the both equation we get 
\tan \alpha =\sqrt{3} and 2u^{2}\cos ^{2}\alpha =2
\alpha = \arctan \sqrt{3} =60\degree
so,\alpha = 60\degree \Rightarrow \cos \alpha = \cos 60\degree =\frac{1}{2}
 
and now 2u^{2}\cos ^{2}\alpha =2
u^{2}\times\left ( \frac{1}{2} \right )^{2} =1
u^{2}=1\times 4
u=\sqrt{4}
u=2

Hence, speed of projection is 2m/s

 
7 days ago
Khimraj
3008 Points
							
Trajectory of projectile motion when u is intial speed inclined Ф angle with horizontal
the equation of projectile is : y = xTanФ - gx²/ 2u²Cos²Ф
and the given equation is : y = √3x - gx²/2
on comparing both the equations ,we get
TanФ = √3
so, Ф = 60°
HENCE, the angle of projectile is 60°
and 2u²Cos²Ф = 2
so u²Cos²Ф = 1
u²cos²60° = 1
u²*(1/2)² = 1
u² = 2²
so, u = 2
7 days ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details