A particle is executing SHM with a period of T sec and amplitude of a metre. The shortest time it takes to reach a point A/√2 m from its mean position in sec will be ?

Question

Kushal · Answer

t/8 is the time taken becoz if we represent the question in a radiant it will form 45 degees with the horizontal so if we take the total time for full oscillation as 360 degrees and for travelling 45 degrees it will take t/8

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A particle is executing SHM with a period of T sec and amplitude of a metre. The shortest time it takes to reach a point A/√2 m from its mean position in sec will be ?

A particle is executing SHM with a period of T sec and amplitude of a metre.
The shortest time it takes to reach a point A/√2 m from its mean position in sec will be ?

1 Answers

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A particle is executing SHM with a period of T sec and amplitude of a metre. The shortest time it takes to reach a point A/√2 m from its mean position in sec will be ?

A particle is executing SHM with a period of T sec and amplitude of a metre.The shortest time it takes to reach a point A/√2 m from its mean position in sec will be ?

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A particle is executing SHM with a period of T sec and amplitude of a metre.
The shortest time it takes to reach a point A/√2 m from its mean position in sec will be ?