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Grade: 12

                        

A particle has initial velocity =3i+4j and a constant force F=4i-3j acts on a particle the path of the particle is 1-straight line 2-parabolic 3-circular 4-elliptical

6 years ago

Answers : (2)

vrun
13 Points
							Here first we will find dot product. 
If a vector X = Ai+Bj and Y  =Ci+Dj,
dot product of X and Y = AC + BD
so 3*4-4*3 = V*F*cosx

So x is 90
This means velocity vector is perpendicular to accelaration and here accelaration is constant. This is the case of parabolic path when it is thrown horizontaly

Hence it is parabolic.
						
6 years ago
vrun
13 Points
							I hope it helps
						
6 years ago
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