A particle has initial velocity (0.3i^+0.4j^)and has acceleration (0.1i^+0.2j^),it's magnitude of displacement after 10seconds is

Question

Saurabh Koranglekar · Answer

Dear student Lets calculate for x part S i^ = ux t + 0.5 ax t*t = 3 + 5= 8i S j^ = uy t + 0.5 ay t*t = 4 + 10 = 14j S = sqrt ( 260) Regards

Khimraj · Answer

V = u + at = 3i +4j + 10(0.3i +0.4j) = 3i +4j +4i + 3j = 7i +7j so magnitude of final velocity is √(7²+7²)= 7√2

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A particle has initial velocity (0.3i^+0.4j^)and has acceleration (0.1i^+0.2j^),it's magnitude of displacement after 10seconds is

A particle has initial velocity (0.3i^+0.4j^)and has acceleration (0.1i^+0.2j^),it's magnitude of displacement after 10seconds is

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A particle has initial velocity (0.3i^+0.4j^)and has acceleration (0.1i^+0.2j^),it's magnitude of displacement after 10seconds is

A particle has initial velocity (0.3i^+0.4j^)and has acceleration (0.1i^+0.2j^),it's magnitude of displacement after 10seconds is

2 Answers

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