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A particle has initial velocity (0.3i^+0.4j^)and has acceleration (0.1i^+0.2j^),it's magnitude of displacement after 10seconds is

Harshith Velraj , 5 Years ago
Grade 12th pass
anser 2 Answers
Saurabh Koranglekar

Last Activity: 5 Years ago

Dear student

Lets calculate for x part

S i^ = ux t + 0.5 ax t*t = 3 + 5= 8i

S j^ = uy t + 0.5 ay t*t = 4 + 10 = 14j

S = sqrt ( 260)

Regards

Khimraj

Last Activity: 5 Years ago

V = u + at = 3i +4j + 10(0.3i +0.4j) 
= 3i +4j +4i + 3j
= 7i +7j

so magnitude of final velocity is √(7²+7²)= 7√2

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