A particle executing SHM from an extreme end of the path towards the centre is observed to be at distances x1, x2 and x3 from the centre, at the ends of three successive seconds. Its time period of oscillation is?

Question

Muntazir Wagay · Answer

X1=acosw×1=acosw X2=axosw×2=acos2w X3=acosw×3 =acos3w Since Cos(theta)=X1+X3/2X2 Therefore Cos(theta) = acosw+acos3w/2acos2w cosw(theta)= cosw Theta = w T= 2pie/theta

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A particle executing SHM from an extreme end of the path towards the centre is observed to be at distances x1, x2 and x3 from the centre, at the ends of three successive seconds. Its time period of oscillation is?

A particle executing SHM from an extreme end of the path towards the centre is observed to be at distances x1, x2 and x3 from the centre, at the ends of three successive seconds. Its time period of oscillation is?

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A particle executing SHM from an extreme end of the path towards the centre is observed to be at distances x1, x2 and x3 from the centre, at the ends of three successive seconds. Its time period of oscillation is?

A particle executing SHM from an extreme end of the path towards the centre is observed to be at distances x1, x2 and x3 from the centre, at the ends of three successive seconds. Its time period of oscillation is?

1 Answers

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Other Related Questions on Wave Motion

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