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A particle executing SHM from an extreme end of the path towards the centre is observed to be at distances x1, x2 and x3 from the centre, at the ends of three successive seconds. Its time period of oscillation is?

A particle executing SHM from an extreme end of the path towards the centre is observed to be at distances x1, x2 and x3 from the centre, at the ends of three successive seconds. Its time period of oscillation is?

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1 Answers

Muntazir Wagay
24 Points
5 years ago
X1=acosw×1=acosw 
X2=axosw×2=acos2w
X3=acosw×3 =acos3w 
   Since 
Cos(theta)=X1+X3/2X2 
  Therefore 
     Cos(theta) = acosw+acos3w/2acos2w 
    cosw(theta)= cosw 
    Theta = w 
  T= 2pie/theta

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