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Grade: 11
        A particle executes simple harmonic motion with an amplitude of 4cm. At mean position the velocity of the particle is 10cm/sec. The distance of the particle from the mean position when its speed becomes 5 cm/s is
one year ago

Answers : (1)

Raghav Jha
37 Points
							As we know in SHM100=16 Omega,henceOmega=100\16(from given value)Now,Again ,5=100/16√A(square)-X(square)Hence X=3.37cm from mean position
						
one year ago
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