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a particel executing shm has an amplitude of 6cm its acceleration at a distance 2cm from mean position is 8cm .the maximum speed is?

sneha babasaheb kakde , 9 Years ago
Grade 12
anser 1 Answers
Ashutosh Mohan Sharma
a= (ω^2)*y
(ω^2)*2= 8
(ω^2) =4 so ω=2rads per second
maxV=A*ω= 6*2=12 cm per secpnd
Last Activity: 9 Years ago
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