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A meter stick swinging from one end oscillates with a frequency f0. What would be the frequency, in terms of f0, if the bottom third of the stick were cut off?
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HI, Its conservation of angular momentum concept! I1f1=I2f2............(1) moment of inertia of rod (stick) in this case is, I= ML2/3. L=lenth of rod(stick) I1=ML2/3 f1=f0 the bottom third of the stick were cut ,final length = 2L/3 final mass =2M/3 I2=(2M/3)(2L/3)2/3 =8ML2/81 put all this values in (1) get f2=27f0/8 ans.
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