A massless rod BD is suspended by two identical massless strings AB and CD equal lengths. A block of mass, ‘m’ is suspended at point P such that BP is equal to ‘x’ . If the fundamental frequency of left wire is twice the fundamental frequency of the right wire, then find the value of ‘x’ .
A massless rod BD is suspended by two identical massless strings AB and CD equal lengths. A block of mass, ‘m’ is suspended at point P such that BP is equal to ‘x’ . If the fundamental frequency of left wire is twice the fundamental frequency of the right wire, then find the value of ‘x’ .
Vignesh , 7 Years ago
Grade 12
