A harmonically moving transverse wave on a string has a maximum particle velocity and acceleration of 3 m/s and 9 m/s2 respectively.Velocity of wave is 20 m/s , then the wave form is
Ravi , 7 Years ago
Grade 11
1 Answers
Vikas TU
Last Activity: 7 Years ago
Dear Student, maximum particle velocity =wA=3 acceleration max=w2A=9 w=3 A=1
Vwave=20
f=w/2π=3/2π v=lf =>l=v/f =>l=20x2π/3 =>l=40π/3
k=2π/l =>k=6/40
The equation of the wave form is= Asin(wt-kx) =sin(3t-6x/40).
Cheers!!
Regards,
Vikas (B. Tech. 4th year Thapar University)
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