Arun
Last Activity: 4 Years ago
For a sine wave, y=Asin(kx−Ωt)Velocity equation for this wave is Vy=ΩAcos(kx−Ωt)Kinetic energy = d(KE)=1/2(Vy2×dm)=1/2(Vy2×μdx), μ is the linear mass density.
=> 1/2(μ×Ω2×A2×cos2(kx−Ωt))dx
integrating at t=0, with limits as 0 and λ, we have
K.E=1/4(μ×Ω2×A2×λ)
Potential energy, dU=1/2(Ω2×y2×μ)dx
integrating at t=0, with limits as 0 and λ, we have
U=1/4(μ×Ω2×A2×λ)
Total energy E=K.E+U
=> E=1/2(μA2λ)
Therefore, for the first and fundamental frequency, energy is
E1=(1/2(μA2λ))/n2
And clearly from the above derivation, we have, K.E is half the total energy.