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a clamped string is oscillating in nth harmonic, then (a) total energy of oscillating will be n^2 times that of fundamental frequency.(b) total energy of oscillations will be (n-1)^2 times that of fundamental frequency.© average kinetic energy of the string over a complete oscillations is half of that of the total energy of the string (D) none of theseMore than one correct type.

Anuj , 6 Years ago
Grade 11
anser 2 Answers
Saurabh Koranglekar

Last Activity: 4 Years ago

Dear student

the total energy of oscillations will be n^2 times that of the fundamental frequency

the average kinetic energy of the string over complete oscillations is half of that of the total energy of the string.

Regards

Arun

Last Activity: 4 Years ago

For a sine wave, y=Asin(kxΩt)
Velocity equation for this wave is Vy=ΩAcos(kxΩt)
Kinetic energy = d(KE)=1/2(Vy2×dm)=1/2(Vy2×μdx)μ is the linear mass density.

=> 1/2(μ×Ω2×A2×cos2(kxΩt))dx
integrating at t=0, with limits as 0 and λ, we have
 
K.E=1/4(μ×Ω2×A2×λ)
Potential energy, dU=1/2(Ω2×y2×μ)dx

integrating at t=0, with limits as 0 and λ, we have
U=1/4(μ×Ω2×A2×λ)

Total energy E=K.E+U
=> E=1/2(μA2λ)
Therefore, for the first and fundamental frequency, energy is 
E1=(1/2(μA2λ))/n2
And clearly from the above derivation, we have, K.E is half the total energy.

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