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A body starting from rest covers a distance of 0.45 km and acquires a velocity of 300 km/hr. Its acceleration will be? (a) 7.72 m/s^2 ans

Medical Student , 7 Years ago
Grade 12th pass
anser 3 Answers
Sandeep Bhamoo
Apply v²-u²= 2as s= 0.45km=450m u= v=300km/hr= 250/3 m/s. On putting these values a= 625/81 m/s² please do approve my answer if correct
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Last Activity: 7 Years ago
Khimraj
v = 300km/hr = 300*5/18m/s = 250/3 m/s
s = 0.45km = 450m
V2 = u2 + 2as
(250/3)2 = 0 + 2a*450 = 900a
So a = 625/81 m/s2
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Last Activity: 7 Years ago
mehak ambreen
Train starts from rest with uniform acceleration of 10 cm sec-2. The velocity after one minute will be
Last Activity: 5 Years ago
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