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A body of mass 4kg hangs from a spring and oscillates with a period 0.5 seconds. On removal of the body the spring shortens by how much?

A body of mass 4kg hangs from a spring and oscillates with a period 0.5 seconds.  On removal of the body the spring shortens by how much?

Grade:12th pass

2 Answers

Saurabh Kumar
askIITians Faculty 2411 Points
6 years ago
At equilibrium, mg = kxeqv

Xeqv = mg/k

Restoring force is developed due to application of extra force during extension.
Rahul shah
13 Points
3 years ago
Hello, 
We know that, T=2π(√m/k)
Putting the value of T, m, after we get 
K=64x9.9~64x10
Then use formula.kx=mg.
X=6.2cm
 
 

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