A body is projected with a speed u m/s at angle β with the horizontal. The kinetic energy at the highest point is 3/4th of the initial kinetic energy. The value of β as?

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Mahima Kanawat · Answer

Dear student... KEi=1/2mu² ; (KE)highest point =1/2mu²cos²β, Ac to given condition 1/2mu²cos²β = 3/4×1/2 mu² ; cosβ=√3/2 and hence β= 30°... WITH REGARDS, MAHIMA (ASKIITIANS FORUM EXPERT)

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A body is projected with a speed u m/s at angle β with the horizontal. The kinetic energy at the highest point is 3/4th of the initial kinetic energy. The value of β as?

A body is projected with a speed u m/s at angle β with the horizontal. The kinetic energy at the highest point is 3/4th of the initial kinetic energy. The value of β as?

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A body is projected with a speed u m/s at angle β with the horizontal. The kinetic energy at the highest point is 3/4th of the initial kinetic energy. The value of β as?

A body is projected with a speed u m/s at angle β with the horizontal. The kinetic energy at the highest point is 3/4th of the initial kinetic energy. The value of β as?

1 Answers

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Other Related Questions on Wave Motion

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