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Wave Motion> . A body executing S.H.M. along a straigh...

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. A body executing S.H.M. along a straight line has a velocity of 3 ms–1 when it is at a distance of 4 m from its mean position and 4 ms–1 when it is at a distance of 3 m from its mean position. Its angular frequency and amplitude are

christy , 8 Years ago

Grade 12th pass

1 Answers

venkat

$v=\omega \sqrt{a^{2}-x^{2}}$

$v_{1}=\omega \sqrt{a^{2}-x_{1}^{2}}$

$3=\omega \sqrt{a^{2}-4^{2}}$

$9=\omega ^{2}(a^{2}-16)$

$\omega ^{2}=9/(a^{2}-16)$ -eqn(1)

$v_{2}=\omega \sqrt{a^{2}-x_{2}^{2}}$

$4=\omega \sqrt{a^{2}-{3}^{2}}$

$16=\omega^{2} ({a^{2}-9})$ -eqn-(2)

After simplifyng eqns-(1) & (2) you will get,

$Angular frequency \ \omega = 1 \ rad/s$

$Amplitude \ a \ = \ 5m$

Approve my answer if it helped you.

Last Activity: 8 Years ago

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