Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A block of mass m rests on a horizontal table, executing SHM along horizontal with amplitude A when blockjust starts to slip then the period ( = coefficient of friction) is
F restoring = F frictionF friction = Ц mgF restoring = mw²ARestoring force on the block = mω2A = μmg.∴ Acceleration in the block = μgFrequency of oscillation,v = 1 / 2 √acceleration / Displacement= 1/2 π √μg / A
Dear student Maximum restoring force = Limiting frictin force mw^2A = μ mgw^A = μgw = sqrt( μg/A)w = 2pie/T T = 2piesqrt(A/ μg)Hope this will help
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -