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A block of mass m rests on a horizontal table, executing SHM along horizontal with amplitude A when block just starts to slip then the period ( = coefficient of friction) is
F restoring = F frictionF friction = Ц mgF restoring = mw²ARestoring force on the block = mω2A = μmg.∴ Acceleration in the block = μgFrequency of oscillation,v = 1 / 2 √acceleration / Displacement= 1/2 π √μg / A
Dear student Maximum restoring force = Limiting frictin force mw^2A = μ mgw^A = μgw = sqrt( μg/A)w = 2pie/T T = 2piesqrt(A/ μg)Hope this will help
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