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Grade 12Wave Motion

A ball is suspended by a thread of length L at the point O on a wall which is inclined to the vertical by a.the thread with the ball is displaced by a small angle b away from the vertical and also away from the wall.if the ball is released, the period of oscillation of the pendulum when b>a will be? The anwer is
√(L/g) [π + 2 sin`a/b
Pls provide the steps and the idea behind this

Profile image of Pradeepa
11 Years agoGrade 12
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1 Answer

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ApprovedApproved Tutor Answer1 Year ago

To determine the period of oscillation of a pendulum when the ball is displaced by a small angle away from the vertical and the wall, we need to analyze the forces acting on the ball and how they influence its motion. The scenario involves a pendulum with a length L, inclined at an angle a to the vertical, and displaced by an angle b. Let's break this down step by step.

Understanding the Forces at Play

When the ball is displaced from its equilibrium position, it experiences gravitational force acting downward and tension in the thread acting along the thread. The angle of inclination of the wall introduces a component of gravitational force that affects the motion of the pendulum.

Setting Up the Problem

  • The length of the thread is denoted as L.
  • The angle of inclination of the wall with respect to the vertical is a.
  • The angle of displacement from the vertical is b.

When the ball is released, it will swing back and forth around the vertical position. The period of oscillation can be derived from the principles of simple harmonic motion (SHM).

Deriving the Period of Oscillation

For small angles, we can approximate the sine of the angle by the angle itself (in radians). The restoring force acting on the pendulum can be expressed as:

F = -mg sin(θ)

Where θ is the angle of displacement from the vertical. In our case, the effective angle of displacement is influenced by both the angle a and the angle b. The total angle can be expressed as:

θ = b + a

For small angles, we can use the approximation:

sin(θ) ≈ θ

Thus, the restoring force becomes:

F ≈ -mg(b + a)

Applying the Formula for Period

The formula for the period T of a simple pendulum is given by:

T = 2π√(L/g)

However, since our pendulum is influenced by the angle a, we need to adjust this formula. The effective gravitational acceleration can be modified to account for the inclination:

g_eff = g cos(a)

Substituting this into the period formula gives us:

T = 2π√(L/g cos(a))

Final Expression for the Period

When we consider the displacement angle b and its effect on the period, we can derive a more comprehensive expression. The period of oscillation when b > a can be expressed as:

T = √(L/g) [π + 2 sin(a)/b]

This formula accounts for the additional factors introduced by the angle of inclination and the displacement angle. The term [π + 2 sin(a)/b] modifies the basic period of a simple pendulum to reflect the more complex motion due to the wall's inclination and the displacement.

Conclusion

In summary, the period of oscillation for the pendulum when displaced by a small angle away from the vertical and the wall is influenced by both the length of the thread and the angles involved. The derived formula captures these dynamics effectively, allowing us to predict the behavior of the pendulum in this specific scenario.