MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

⇐ BackProceed to Checkout ⇒
There are no items in this cart.
Continue Shopping
Menu
Grade: 11 
        
A 95.2-kg solid sphere with a 14.8-cm radius is suspended by a vertical wire attached to the   ceiling of a room. A torque of 0.192 N· m is required to swist the sphere through an angle of  0.850 rad. Find the period of oscillation when the sphere is released from this position.
3 years ago

Answers : (1)

Jitender Pal
askIITians Faculty
365 Points 
							235-895_1.PNG
3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Other Related Questions on Wave Motion

the time reverberation of an empty hall without and with 500 audience is 1.5s and 1.4 s find the... Answer & Earn Cool Goodies
A block of mass m is attached to a spring and is placed on a platform and the spring at this stage... Answer & Earn Cool Goodies
time period of simple pendulum whose length is 88.2cm will be (g=9.8m/s2
A particle is executing SHM with a period of T sec and amplitude of a metre. The shortest time it...
let the fundamental frquency is 45hz and the length of the wire is 87.5cm. If the linear density of...
View all Questions »


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers To Win!!! Click Here for details