MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Radhika Batra Grade: 11
        
A 3.94-kg block extends a spring 15.7 cm from its unstretched position. The block is removed and a 0.520-kg object is hung from the same spring. Find the period of its oscillation.
2 years ago

Answers : (2)

Aditi Chauhan
askIITians Faculty
396 Points
										To find out the force constant k, substitute 3.94 kg for mass of the block m, 9.81 m/s2 for g and 15.7 cm for x in the equation k = mg/x,
k = mg/x
= (3.94 kg) (9.81 m/s2) / (15.7 cm)
= (3.94 kg) (9.81 m/s2) / (15.7 cm×10-2 m/1 cm)
= (0.246 kg. m/s2) / m
= (0.246 kg. m/s2× (1 N/1 kg.m/s2)) / m
= 0.246 N/m
To obtain the period T of oscillation, substitute 0.246 N/m for k and 0.520 kg for mass of the object M in the equation T = 2π √M/k,
T = 2π √M/k
= 2×3.14×√(0.520 kg)/( 0.246 N/m)
= 0.289 √kg/(N/m) (1 kg.m/s2 /1 N)
= 0.289 s
From the above observation we conclude that, the period of oscillation would be 0.289 s.
2 years ago
pa1
357 Points
										
/1 N)= 0.289 sFrom the above observation we conclude that, the period of oscillation would be 0.289 s.2)) / m = 0.246 N/mTo obtain the period T of oscillation, substitute 0.246 N/m for k and 0.520 kg for mass of the object M in the equation T = 2π √M/k,T = 2π √M/k = 2×3.14×√(0.520 kg)/( 0.246 N/m) = 0.289 √kg/(N/m) (1 kg.m/s2× (1 N/1 kg.m/s2) / m = (0.246 kg. m/s2 m/1 cm) = (0.246 kg. m/s-2) / (15.7 cm×102) / (15.7 cm) = (3.94 kg) (9.81 m/s2 for g and 15.7 cm for x in the equation k = mg/x,k = mg/x = (3.94 kg) (9.81 m/s2To find out the force constant k, substitute 3.94 kg for mass of the block m, 9.81 m/s
2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: Rs. 2,756
  • View Details
  • Complete Physics Course - Class 11
  • OFFERED PRICE: Rs. 2,968
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details