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Grade: 12th pass
        
A 20cm long rubber string obeys hookes law. When it is stretched by 4 cm ,its lowest resonant frequency is Vo. When it is further stretched by 2cm, find whether the new lowest resonant frequency is greater than or less than or equal to Vo. 
9 months ago

Answers : (3)

Shivansh
askIITians Faculty
267 Points
							Resonant frequency is independent of stretching. It only depends on mass and hooke’s constant
						
9 months ago
Pawan joshi
26 Points
							
But answer in my book is given greater than Vo.. ..Without any explanation.... . ........... . ....... ...... ...... 
9 months ago
Shivansh
askIITians Faculty
267 Points
							In that case you can assume that the string will follow the hooke’s law only for half of it’s path. When it reaches the mean position, it follows simple motion under gravity. Because it is thrown up with a lesser speed as compared to the first case, it will come back faster, hence the total time taken will decrease. That explains why frequency will be more.
Hope that answers your quesiton
9 months ago
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  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


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