Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A 0.1 kg ball is attached to a string 1.2 m long and suspended .at 0.2m below suspension point a peg is placed which string hits when the pendulum comes down. If the mass is pulled a small distance to one side and released. What will be the time period of motion........ Ans: 2.1s

A 0.1 kg ball is attached to a string 1.2 m long and suspended .at 0.2m below suspension point a peg is placed which string hits when the pendulum comes down. If the mass is pulled a small distance to one side and released. What will be the time period of motion........ Ans: 2.1s

Grade:12th pass

1 Answers

Arun
25763 Points
2 years ago
Dear Pawan
 
Time period will be = pi * (sqrt (1.2) + 1) / sqrt(g) = 2.1 sec
 
hope it helps
 
Regards
Arun (askIITians forum expert)

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free