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A 0.1 kg ball is attached to a string 1.2 m long and suspended .at 0.2m below suspension point a peg is placed which string hits when the pendulum comes down. If the mass is pulled a small distance to one side and released. What will be the time period of motion........ Ans: 2.1s

Pawan joshi , 7 Years ago
Grade 12th pass
anser 1 Answers
Arun
Dear Pawan
 
Time period will be = pi * (sqrt (1.2) + 1) / sqrt(g) = 2.1 sec
 
hope it helps
 
Regards
Arun (askIITians forum expert)
Last Activity: 7 Years ago
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