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If the eq of trajectory of a projectile is given, how to find the time of its flight. For eg if eq of trajectory is y=ax -bx2 where y is height n x is horizontal dist from the pt of projection, how to get d time of flight??
Consider @ as Theta
The motion of trajectory is y=xtan@ - (1* g*x2) / 2 * u2cos2@
So, x = ucos@ *t -- eqn.(1)
also, from eqn(1), we get
x / ucos@ = t;
so in the equation of trajectory, x2/u2cos2@ = t2
putting t2 in the equation of the trajectory we get,
y = xtan@ - (1/2 * g * t2)
also, xtan@ = x* usin@/ucos@
solve like this u will get...
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