#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-5470-145

+91 7353221155

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# The extension in a string (obeying Hooke's law)  is x. The speed of sound in the stretched string is v. If the extension in the string is increased to 1.5x, what would the speed of sound be?

SAGAR SINGH - IIT DELHI
879 Points
11 years ago

Dear student,

v/x=v'/1.5x

v'=1.5v

All the best.

Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.

Sagar Singh

B.Tech, IIT Delhi

sapna .
14 Points
9 years ago

acc to me the correct answer is 1.22v as v is proportional to √x.

Maurya Sharma
13 Points
2 years ago
Y=Fl/A∆l

F=(YA/l) ∆l
F js Directly proportional to change in length

According to wave motion, v is Directly proportional to √F

Therefore, v is directly proportional to √∆l

V=kx
V'=k√1.5x
V'=1.22v

ankit singh
one year ago

Y=Fl/A∆l

F=(YA/l) ∆l
F js Directly proportional to change in length

According to wave motion, v is Directly proportional to √F

Therefore, v is directly proportional to √∆l

V=kx
V'=k√1.5x
V'=1.22v