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In YDSE interference fringes of width w are obtained with blue light of wavelength 4861 angstrom. Find fringe width when blue light is replaced with red light of wavelength 6563 angstrom & the entire set up is simultaneously immersed in a liquid of refractive index 1.35.

sonali goyal , 12 Years ago
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Askiitians Tutor Team

To determine the fringe width when the blue light is replaced with red light in a Young's Double Slit Experiment (YDSE) while also considering the effect of immersing the setup in a liquid, we can follow a systematic approach. The fringe width in YDSE is influenced by the wavelength of the light used and the medium in which the experiment is conducted.

Understanding Fringe Width

The fringe width (w) in YDSE is given by the formula:

w = λD / d

Where:

  • w = fringe width
  • λ = wavelength of the light used
  • D = distance between the slits and the screen
  • d = distance between the slits

Effect of Medium on Wavelength

When the entire setup is immersed in a liquid with a refractive index (n), the wavelength of light in that medium changes. The new wavelength (λ') can be calculated using the formula:

λ' = λ / n

Here, λ is the original wavelength of the light in vacuum, and n is the refractive index of the liquid.

Calculating the New Fringe Width

First, let's find the new wavelength for both blue and red light when immersed in the liquid with a refractive index of 1.35.

For Blue Light

The wavelength of blue light is given as 4861 Å (angstroms), which is equivalent to:

λ_blue = 4861 × 10-10 m

Now, substituting into the formula for the new wavelength:

λ'_blue = λ_blue / n = (4861 × 10-10) / 1.35

Calculating this gives:

λ'_blue ≈ 3601.48 × 10-10 m

For Red Light

The wavelength of red light is 6563 Å, which is:

λ_red = 6563 × 10-10 m

Now, applying the same formula for the new wavelength:

λ'_red = λ_red / n = (6563 × 10-10) / 1.35

Calculating this gives:

λ'_red ≈ 4869.63 × 10-10 m

Finding the New Fringe Width

Now, we can find the fringe width for the red light using the new wavelength:

Since the distance between the slits (d) and the distance to the screen (D) remain unchanged, we can express the new fringe width (w') as:

w' = λ'_red D / d

Since we are looking for the ratio of the fringe widths when changing from blue to red light, we can compare:

w' / w = λ'_red / λ'_blue

Substituting the values we calculated:

w' / w = (4869.63 × 10-10) / (3601.48 × 10-10)

This simplifies to:

w' / w ≈ 1.352

Final Calculation

If the original fringe width (w) with blue light was known, the new fringe width (w') can be calculated as:

w' ≈ 1.352 × w

Thus, the fringe width when blue light is replaced with red light in the liquid will be approximately 1.352 times the original fringe width obtained with blue light.

This demonstrates how the wavelength of light and the refractive index of the medium can significantly affect the interference pattern in YDSE. If you have any further questions or need clarification on any part of this process, feel free to ask!

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