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5)A loudspeaker has a circular opening with a radius of 0.0950m.Theelectrical power needed to operate the speaker is 25.0W.The averagesound intensity at the opening is 17.5W/m.m.What percentage of theelectrical power is converted by the speaker into sound power?

Arjun Varkal , 11 Years ago
Grade 12
anser 1 Answers
Abhishek Kumar

Last Activity: 9 Years ago

Power = 25.
X/Surface area = 17.5 (Let X is converted to sound energy)
X/Surface area x Area of the circular opening = 17.5
Find X.

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