A wave of frequency 500Hz has a velocity 360m/s. The distance between two nearest points which are 60 degree out of phase is ....?

please explain

Question

A wave of frequency 500Hz has a velocity 360m/s. The distance between two nearest points which are 60 degree out of phase is ....? please explain

Shivam Dimri · Answer

firts finding the wavelength

k = speed/frequency

=> k =36/50

now phase difference = (2∏/k )* path difference

60 = (360/36) * 50 * path difference

distance bewtween two nearest points is = path difference = 6/50 metre

got it!!

Ryhhg · Answer

firts finding the wavelengthk = speed/frequency=> k =36/50now phase difference = (2∏/k )* path difference60 = (360/36) * 50 * path differencedistance bewtween two nearest points is = path difference = 6/50 metre

Praneeth · Answer

K=v/f K=360/500=36/50 Phase difference=2pie/k ×dx 60=360×50×dx/36 dx=12cm 60=360/36 ×50×dxnger dx=12cm

Kushagra Madhukar · Answer

Dear student, Please find the solution to your problem. k = speed/frequency => k = 36/50 now phase difference = (2 π /k ) x path difference π /3 = (2 π/36 x 50) x path difference Hence, the distance bewtween two nearest points = path difference = 0.12 m = 12 cm Thanks and regards, Kushagra

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A wave of frequency 500Hz has a velocity 360m/s. The distance between two nearest points which are 60 degree out of phase is ....? please explain

A wave of frequency 500Hz has a velocity 360m/s. The distance between two nearest points which are 60 degree out of phase is ....?

please explain

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