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A wave of frequency 500Hz has a velocity 360m/s. The distance between two nearest points which are 60 degree out of phase is ....?
please explain
firts finding the wavelength
k = speed/frequency
=> k =36/50
now phase difference = (2∏/k )* path difference
60 = (360/36) * 50 * path difference
distance bewtween two nearest points is = path difference = 6/50 metre
got it!!
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