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A person standing on the floor of an elevator drops a coin. The coin reaches the floor of the elevator in a time t1 if the elevator is stationary and in time t2 if it is moving uniformly. Then: (a) t1 = t2 (b) t1 t2 or t1


A person standing on the floor of an elevator drops a coin. The coin reaches the floor of the elevator in a time


t1 if the elevator is stationary and in time t2 if it is moving uniformly. Then:


(a) t1 = t2 (b) t1 < t2 (c) t1 > t2 or t1 < t2 depending on whether the lift is going up or down.


Grade:11

4 Answers

Anirban Mukherjee
47 Points
10 years ago

If lift is moving with uniform velocity its same as its in rest

so t1=t2

G Ashwin -
24 Points
9 years ago

when it moves with same speed/velocity

acceleration=0.

at rest also , a=0.

therefore,

t1=t2

Harmeet
19 Points
5 years ago
When it`s dropped in uniform motion of elevator ,it`s the same distance covered by coin when dropped at rest.
Priyanshu Thakur
15 Points
3 years ago
The answer is t1=t2 because there is no change in acceleration as it move uniformly .So there's is no change in time
 

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