Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A person standing on the floor of an elevator drops a coin. The coin reaches the floor of the elevator in a time t1 if the elevator is stationary and in time t2 if it is moving uniformly. Then: (a) t1 = t2 (b) t1 t2 or t1


A person standing on the floor of an elevator drops a coin. The coin reaches the floor of the elevator in a time


t1 if the elevator is stationary and in time t2 if it is moving uniformly. Then:


(a) t1 = t2 (b) t1 < t2 (c) t1 > t2 or t1 < t2 depending on whether the lift is going up or down.


Grade:11

4 Answers

Anirban Mukherjee
47 Points
9 years ago

If lift is moving with uniform velocity its same as its in rest

so t1=t2

G Ashwin -
24 Points
8 years ago

when it moves with same speed/velocity

acceleration=0.

at rest also , a=0.

therefore,

t1=t2

Harmeet
19 Points
4 years ago
When it`s dropped in uniform motion of elevator ,it`s the same distance covered by coin when dropped at rest.
Priyanshu Thakur
15 Points
2 years ago
The answer is t1=t2 because there is no change in acceleration as it move uniformly .So there's is no change in time
 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free