The potential energy of a particle executing SHM alon x-axis is U=U0(1-cosax).What is the frequency of oscillation?

							
Dear student
U=U0(1-cosax)
Force=-dU/dx=-aU0sinax=-w^2 (x)
from here you can easliy calculate frequency on comparing the two..








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U = U0(1-cosax)
F = -dU/dx = -Uoasinax
for small x , sinax is small or sinax = ax
F = -U0a2x
a = -Uoa2x/m                              (a = -w2x)
-w2x = -Uoa2x/m
 w = (Uoa2/m)1/2
						

							U = U0(1-cosax)
F = -dU/dx = -Uoasinax 
for small x , sinax is small or sinax = ax 
F = -U0a2x
a = -Uoa2x/m                              (a = -w2x)
-w2x = -Uoa2x/m
 w = (Uoa2/m)1/2